Problem 1283
In the sequence of numbers 2001, 2002, 2003, 2000, . . . each term after the third term is found by subtracting the previous term from the sum of the two preceding terms. Therefore, the fourth term 2000 is found by 2001 + 2002 – 2003 = 2000. The fifth term will be found by 2002 + 2003 – 2000 = 2005. What will be the 101st term?
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